4c=(1/2)((c^2+6)+(c^2+2))

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Solution for 4c=(1/2)((c^2+6)+(c^2+2)) equation: 


c in (-oo:+oo)

4*c = (1/2)*(c^2+c^2+2+6) // - (1/2)*(c^2+c^2+2+6)

4*c-((1/2)*(c^2+c^2+2+6)) = 0

(-1/2)*(c^2+c^2+2+6)+4*c = 0

4*c-1/2*(2*c^2+8) = 0

4*c-1/2*(2*c^2+8) = 0

4*c-c^2-4 = 0

4*c-c^2-4 = 0

4*c-c^2-4 = 0

DELTA = 4^2-(-4*(-1)*4)

DELTA = 0

c = -4/(-1*2)

c = 2 or c = 2

(c-2)^2 = 0

(c-2)^2 = 0

c-2 = 0 // + 2

c = 2

c in { 2, 2 }

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